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up vote 1 down vote favorite

Lets say you are having a user provide information. 

Array 1

But not all is required. So you have defaults.

Array 2

Does PHP have a function which will overwrite all array values of Array 2 based on if they are supplied in Array 1, and not empty?

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3 Answers

up vote 3 down vote accepted

I'm not sure either of these answers are helping you out (they didn't help me) especially for the case when your "defualts" may be an associative array more than one level deep.

I think what you are looking for is array_replace_recursive.
$finalArray = array_replace_recursive(array $defaults, array $inputOptions)

heres an example that takes an optional array of options to a function and does some processing based on the result of those options "opts" and the defaults which you specify:

function do_something() {
    $args = func_get_args();
            $opts = $args[0] ? $args[0] : array();

    $defaults = array(
        "second_level" => array(
                    "key1" => "val1",
                    "key2" => "val2"
                ),
        "key1" => "val1",
        "key2" =>  "val2",
        "key3" => "val3"
    );

    $params = array_replace_recursive($defaults, $opts);
    // do something with these merged parameters
}

Check it out here

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That would have been great! TY –  Orangeman555 Dec 18 '13 at 6:47
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up vote 2 down vote

array_merge() is exactly what you are looking for.

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up vote 1 down vote

You can just do something like

foreach($array1 as $key=>$value) $array2[$key]=$value;
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