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up vote 1 down vote favorite

I'm trying to convert a PHP multidimensional array to a javascript array using the JSON encoder. When I do a var_dump, my php array looks like this:

array (size=2)
  'Key' => string 'a' (length=1)
  'Value' => string 'asite.com' (length=9)

This is the code I'm currently using in my view to try to convert it to a JavaScript array:

var tempArray = $.parseJSON(<?php echo json_encode($php_array); ?>);

Whenever I run this code in the browser, the output of the conversion in the console is this:

var tempArray = $.parseJSON([{"Key":"a","Value":"asite.com"}]);

Is this the correct structure for a javascript multidimensional array? I'm asking because it keeps giving me this error on the line above:

SyntaxError: Unexpected token o

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4 Answers 4

up vote 4 down vote accepted

You do not have to call parseJSON since the output of json_decode is a javascript literal. Just assign it to a variable.

var tempArray = <?php echo json_encode($php_array); ?>;

You should be able then to access the properties as 

alert(tempArray[0].Key);
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That worked perfectly, thank you –  user1186173 Jun 11 '13 at 15:41
up vote 2 down vote

This worked for me.

<script type='text/javascript'>
<?php
    $php_array = array(
        array("casa1", "abc", "123"), 
        array("casa2", "def", "456"), 
        array("casa3", "ghi", "789" )
    );

    $js_array = json_encode($php_array);
    echo "var casas = ". $js_array . ";\n";
?>

alert(casas[0][1]);

</script>
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up vote 0 down vote

Do not use parseJSON, that's for a string. Just do:

<?php
$php_array = array ('Key'=>'a', 'Value'=>'asite.com');
?>
<html>
<head>

    <script type="text/javascript">
    var tempArray = <?php echo json_encode($php_array); ?>;
    console.log(tempArray);
    </script>
</head>
<body>
</body>
</html>

This give me in the console:

Object { Key="a", Value="asite.com"}
share|improve this answer
    
I didn't realize it was only for strings, thanks for the answer. –  user1186173 Jun 11 '13 at 15:44
up vote -1 down vote

Just add single quotes in the js function,like

var tempArray = $.parseJSON('<?php echo json_encode($php_array); ?>');

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