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I am trying to generate random array of integers using new Stream API in Java 8. But I haven't understood this API clearly yet. So I need help. Here is my code. 

Random random = new Random();
IntStream intStream = random.ints(low, high);
int[] array =  intStream.limit(limit) // Limit amount of elements
                                    .boxed() // cast to Integer
                                    .toArray();

But this code returns array of objects. What is wrong with it?

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2 Answers 2

up vote 3 down vote accepted

Simply use Random.ints which returns an IntStream:

int[] array = new Random().ints(limit, low, high).toArray();
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Can you please explain what is the purpose of using boxed ? –  ketazafor Sep 11 '14 at 17:18
2  
@ketazafor: You'd only want to use boxed() if you did want an object array instead of an int[]. That's your whole problem. –  Louis Wasserman Sep 11 '14 at 17:22
    
Thx for answer, one more question is there any elegant way to generate randow string using stream api ? –  ketazafor Sep 11 '14 at 17:24
1  
@ketazafor: depends on how your random String should be constructed. If it should interpret each random int as code point, combine the int stream of this answer with “Simplest way to print an IntStream as a String” –  Holger Sep 11 '14 at 17:47
up vote 2 down vote

There's no reason to boxed(). Just receive the Stream as an int[].

int[] array = intStream.limit(limit).toArray();
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