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up vote 23 down vote favorite
13

I would like to convert this string

{"id":1,"name":"Test1"},{"id":2,"name":"Test2"}

to array of 2 JSON objects. How should I do it?

best

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2  
If you get this as a JSON string, then it is not valid JSON anyway... where do you get it from? Could you post a more complete code example? –  Felix Kling Dec 7 '10 at 10:22

6 Answers 6

up vote 43 down vote accepted

Using jQuery:

var str = '{"id":1,"name":"Test1"},{"id":2,"name":"Test2"}';
var jsonObj = $.parseJSON('[' + str + ']');

jsonObj is your JSON object.

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Thanks a lot for answers –  Sobis Dec 7 '10 at 12:02
    
@Sobis You could have accepted an answer... –  shasi kanth Apr 11 '11 at 12:15
up vote 8 down vote

As Luca indicated, add extra [] to your string and use the code below:

var myObject = eval('(' + myJSONtext + ')');

to test it you can use the snippet below.

var s =" [{'id':1,'name':'Test1'},{'id':2,'name':'Test2'}]";
var myObject = eval('(' + s + ')');
for (i in myObject)
{
   alert(myObject[i]["name"]);
}

hope it helps..

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it works fine with this solution –  Anup Sep 15 '14 at 11:27
up vote 5 down vote

Append extra an [ and ] to the beginning and end of the string. This will make it an array. Then use eval() or some safe JSON serializer to serialize the string and make it a real JavaScript datatype.

You should use https://github.com/douglascrockford/JSON-js instead of eval(). eval is only if you're doing some quick debugging/testing.

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up vote 3 down vote

If your using jQuery, it's parseJSON function can be used and is preferable to JavaScript's native eval() function.

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up vote 0 down vote

I know a lot of people are saying use eval. the eval() js function will call the compiler, and that can offer a series of security risks. It is best to avoid its usage where possible. The parse function offers a more secure alternative.

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up vote -2 down vote

As simple as that.

var str = '{"id":1,"name":"Test1"},{"id":2,"name":"Test2"}'; dataObj = JSON.parse(str);

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As the comment on the original question states, the string as given is not valid JSON. –  Adrian Wragg Mar 10 '14 at 12:44

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