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up vote -1 down vote favorite

Noob learning to become a Web developer here. On a PHO module of my study course right now and hitting a bit of a bug.

Anyone able to explain to me why unset($name); is causing an error message to get thrown?

Any help would be greatly appreciated :)

<?php

$myArray=array("pizza","chocolate","coffee");

print_r($myArray);

echo $myArray[1];

echo "<br /><br />";

$anotherArray[0]="pizza";
$anotherArray[1]="yoghurt";

print_r($anotherArray);

echo "<br /><br />";

$thirdArray=array(

    "France" => "French",
    "USA" => "English",
    "Germany" => "German",

);

print_r($thirdArray);

$anotherArray[]="salad";

echo "<br /><br />";

print_r($anotherArray);

echo "<br /><br />";

unset($thirdArray["Germany"]);

print_r($thirdArray);

echo "<br /><br />";

$name="Rob";

unset($name);

echo $name;

?>
share|improve this question
8  
after unset($name) you are trying to echo it so it throws error –  Manadh 19 hours ago
    
you are echoing unset variable thats why you got error –  Navneet Garg 19 hours ago

1 Answer 1

up vote 0 down vote accepted

You cannot use any variable you have just unset(). unset() is here to explicitly destroy a variable that cannot be longer used.

Therefore, it should be:

<?php
// first, set $name
$name = 'Rob';
// then, use it
echo $name;
// at last, unset it
unset($name);

echo $name // will finally output an error.

Instead of the other way around.

share|improve this answer
    
Okay I understand now! Thanks very much :) –  Sean Ravenhill 18 hours ago
    
Glad you made it work! Please also consider upvoting the answer if it helped you. –  D4V1D 18 hours ago
    
@SeanRavenhill I just upvoted your question btw :) –  D4V1D 16 hours ago

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