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up vote 1 down vote favorite

I have a sting which contains a date, but date object wont accept it, so i have to make it into a valid format.

I tried this

"20130820".split(/^[a-z0-9]{4}[a-z]{2}[a-z0-9]{2}?$/)

It should give out an array like 

["2013", "08", "20"]

Any idea where i am wrong?

share|improve this question
    
what was your intention in adding [a-z] characters to the regex? Do you expect to get alphanumeric values? –  devnull69 Oct 1 '13 at 14:53
    
Users never can be to... you get it.. –  Sangoku Oct 1 '13 at 14:59

3 Answers 3

up vote 3 down vote accepted

You want to use .match rather than .split. You need to capture each group, and the second character class is also a-z when it should probably just be \d.

"20130820".match(/^(\d{4})(\d{2})(\d{2})$/).slice(1)
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up vote 1 down vote

Why split, you can use String#match:

var m = "20130820".match(/^(\d{4})(\d{2})(\d{2})$/);
//=> ["20130820", "2013", "08", "20"]

btw for this simple job you don't need regex just use String#substring

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up vote 0 down vote

try substring 

   String str="20130820";
   String  year=str.subString(0,3);
   String  month=str.subString(4,5);
   String  date=Str.subString(6,7);
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