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up vote 0 down vote favorite

I simply want to plot "a vs b" in a log-log scaled plot, but I get an error.

import matplotlib.pyplot as plt

a = [7255.151855, 231.589661, 9.365415, 0.55364, 1.5001, 0.006408, 0.001204, 0.000842]
b = [0.212399, 0.393191, 0.727874, 1.347436, 2.494368, 4.617561, 8.548006, 15.824027]

CyclesPerBlock = 219397
LoadAmplitude = 4990

a = [x*CyclesPerBlock for x in a]
b = [y*LoadAmplitude for y in b]

fig = plt.plot
fig.set_xscale("log")
fig.set_yscale("log")
fig.set_xlim(1e-3, 1e4)
fig.set_ylim(1e-1, 1e3)
fig.set_aspect(1)
fig.set_title("Calculation Results")

fig.plot(a, b, "o-")
plt.draw()
plt.show()
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You got an answer, but it is better to include the full traceback when posting your question. It is also best to post the minimum amount of code required to generate the issue. –  tcaswell May 23 '14 at 13:29

1 Answer 1

up vote 4 down vote accepted

You have to create the AxesSubplot object first, and then use it to plot:

fig = plt.figure()
ax = fig.add_subplot(111)
ax.set_xscale("log")
ax.set_yscale("log")
ax.set_xlim(1e-3, 1e4) # <-- check this as pointed out by @tillsten
ax.set_ylim(1e-1, 1e3) # <--
ax.set_aspect(1)
ax.set_title("Calculation Results")

ax.plot(a, b, "o-")
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1  
Also your xlim and ylim are wrong. –  tillsten May 23 '14 at 12:37

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