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up vote 0 down vote favorite

i am trying to fetch data from MySQL and show it in JSON format This is the partial PHP code

$sql = "SELECT item, cost, veg, spicy_level FROM food1";
$result = $conn->query($sql);

    while($row = $result->fetch_assoc()) {

    echo  json_encode($row),"<br/>";}

?> i am getting output as 

{"item":"dosa","cost":"20","veg":"0","spicy_level":"1"}
{"item":"idli","cost":"20","veg":"0","spicy_level":"2"}

but i need it as

food1:[
{"item":"dosa","cost":"20","veg":"0","spicy_level":"1"},
{"item":"idli","cost":"20","veg":"0","spicy_level":"2"}
]

can anyone please guide me? i think what i am getting is in object format and i need output in array format i.e. with [ & ]. very new to this json and php.

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3 Answers 3

up vote 0 down vote accepted

You can incapsulate query results in array and after print it;

$sql = "SELECT item, cost, veg,     spicy_level FROM food1";
$result = $conn->query($sql);
$a = array();
while($row = $result->fetch_assoc()) {
  if($a['food1'] ==null)
     $a['food1'] = array():
  array_push($a['food1'],$row);}


  echo json_encode($a);
?></i>
share|improve this answer
    
it worked, thanks! –  saurabhC Mar 5 at 7:48
up vote 0 down vote

Don't call json_encode each time through the loop. Put all the rows into an array, and then encode that.

$food = array();
while ($row = $result->fetch_assoc()) {
    $food[] = $row;
}
echo json_encode(array('food1' => $food));
share|improve this answer
up vote 0 down vote

Your code should be :

$sql = "SELECT item, cost, veg, spicy_level FROM food1";
$result = $conn->query($sql);

$food['food1'] = array();

while($row = $result->fetch_assoc()) {
    $food['food1'][] = $row;    
}

echo  json_encode($food);
share|improve this answer
    
thanks, tried it bt it shows null –  saurabhC Mar 5 at 7:38
    
sorry... it was typo... updated the code... change the last line –  Gopakumar Gopalan Mar 5 at 7:43

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