0

I am trying to build a re-usable function for pulling json results and writing back to the page

so far i get the json and when its returned run a function that passes some data the index and the result. That all works fine

The problem is when I went to do an iteration around the result in the function (seen below)

sometimes the data structure could be data.userGroup.form and other times data.userGroup.user and so on

what i have tried to do is pass the name i want to use into the function as the last argument i.e. "user" and the wihin the inner .each call element.name (where name can vary) but this doesnt work. can anyone help?

here is the code

$.when(promise).then(function(result) {

    $(result.data.userGroup).each(function(index, element) {
    var html = getHTML( ["Name", "Delete"], index, element, "user");

        $("#accordion2").append(html);
    });

})

function getHTML(array, index, element, name) {

var html = " <div class='accordion-group'>";
html = html + "<div class='accordion-heading'>";
html = html + "<span class='accordian-image'></span>" + element.name + "</a>";
var inner ="";

    $(element.name).each(function(i, result) {
    inner = inner + "<tr><td>" + result.name + "</td>" ;
    });

html = html + inner;
return html;
}

1 Answer 1

1

You need to use the bracket notation instead of dot notation as the member operator.

element[name]

Ex

$.when(promise).then(function(result) {

    $(result.data.userGroup).each(function(index, element) {
        var html = getHTML( ["Name", "Delete"], index, element, "user");

        $("#accordion2").append(html);
    });

})

function getHTML(array, index, element, name) {

    var html = " <div class='accordion-group'>";
    html = html + "<div class='accordion-heading'>";
    html = html + "<span class='accordian-image'></span>" + element[name] + "</a>";
    var inner ="";

    $(element.name).each(function(i, result) {
        inner = inner + "<tr><td>" + result[name] + "</td>" ;
    });

    html = html + inner;
    return html;
}
Sign up to request clarification or add additional context in comments.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.