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up vote 0 down vote favorite

I currently have 2 arrays where i would like to compare dates in. here are how my arrays are structured:

$bholidays = array('05-05-2014','26-05-2014');

$userdaysoff = array('23-05-2014','24-05-2014','25-05-2014', '26-05-2014');

The aim is to detect whether or not a value from $userdaysoff exists in the $bholidays array.

The above works great and detects that 26-05-2014 exists in both arrays, but if the $userdaysoff array looks like this:

$userdaysoff = array('26-05-2014','27-05-2014','28-05-2014', '29-05-2014');

Then the duplicate date 26-05-2014 is not detected.

Is there any reason why this would be occuring?

here is how i run my code:

$results = array_intersect($bholidays, $userdaysoff);
if($results){



foreach($results as $result){

echo 'yes';

}

} else {

echo 'no';  

}
share|improve this question
    
Please run your code carefully. It runs fine. –  Rolen Koh Mar 19 '14 at 10:23
    
Yes it does works correctly... –  amit Mar 19 '14 at 10:25
    
and whats the output u get?? –  amit Mar 19 '14 at 10:32
    
if i structure the array like my top example it works and $results returns a result of yes, the second example returns no –  danyo Mar 19 '14 at 10:33
    
Check my updated answer. –  amit Mar 19 '14 at 10:36

3 Answers 3

up vote 0 down vote

Could you not quite simply use in_array?

$bholidays = array('05-05-2014','26-05-2014');
$userdaysoff = array('23-05-2014','24-05-2014','25-05-2014', '26-05-2014');

$count = count($userdaysoff);
for($i = 0; $i == $count; $i++) {
    if(in_array($userdaysoff[$i], $bholidays)) {
        echo $userdaysoff[$i] . " is in array.";
    }
 }
share|improve this answer
up vote 0 down vote 
    $bholidays = array('05-05-2014','26-05-2014');
$userdaysoff = array('26-05-2014','27-05-2014','28-05-2014', '29-05-2014');

$results = array_intersect($bholidays, $userdaysoff);
if($results)
{
    foreach($results as $result)
    {
        echo 'yes';
    }
}
else
{
    echo 'no';
}

Run this code and check it works fine..

The output is yes.

share|improve this answer
    
this is my exact code i have posted in my question? –  danyo Mar 19 '14 at 10:38
    
It is working fine.. Thats what iam trying to tell u... –  amit Mar 19 '14 at 10:40
    
yes, but it isnt for me –  danyo Mar 19 '14 at 10:43
    
how can it not? what is the php version? –  amit Mar 19 '14 at 10:44
up vote 0 down vote

@danyo, seems you have copied pasted string and it has some extra bytes otherwise your code is correct and working fine.

share|improve this answer

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