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up vote 0 down vote favorite

I'm trying to sort this array on vCount (descending) but I can't figure out how to do so. I've searched stack overflow but I can't find anything similar to my issue.

This is what I came up with this far, I guess this doesn't work because vCount is deeper in the array but how do I get deeper in the array within the sort function?

var nar = trck_urls.sort(function(a, b){ // trck_urls is the array
  return b['vCount'] - a['vCount'];
});

This is the array I'm trying to sort. (console.log output)

[ '/home': [ pageTitle: 't1',
    Visitors: [ 'oPc-Gr6SYxN1AMyw8Pst' ],
    vCount: 1 ],
  '/dash': [ pageTitle: 't2',
    Visitors: [ 'jepoSdBR9_ur3XSu8Psu', 'WIO4fEt1Ue8yHCly8Psv' ],
    vCount: 2 ] ]
share|improve this question
    
array has invalid object syntax in it, can't sort an object – charlietfl May 25 '14 at 20:11
    
FYI About objects sorting – Dalorzo May 25 '14 at 20:31
    
If that's the output of console.log, you've abused JavaScript arrays. If it's your script, then you've got a syntax error. – Bergi May 25 '14 at 20:42
    
@Dalorzo thats not a issue because it's for Node.JS but thanks for mentioning it. – Tim K May 25 '14 at 20:46
    
@Bergi console.log output yes. Will read that article later when I have some more time. – Tim K May 25 '14 at 20:48

2 Answers 2

up vote 0 down vote accepted

I suggest you coerce your data structure into something easily sortable like this:

var trck_urls = [
  { path:'/home',
    pageTitle: 't1',
    Visitors: ['oPc-Gr6SYxN1AMyw8Pst'],
    vCount: 1 },
  { path:'/dash',
    pageTitle: 't2',
    Visitors: ['jepoSdBR9_ur3XSu8Psu', 'WIO4fEt1Ue8yHCly8Psv' ],
    vCount: 2 }
];

var sorted = trck_urls.sort(function(a,b){
    return b.vCount - a.vCount;
});

If you need to store the data as an object, you can coerce the object into an array whenever you need to sort it, like this:

var sortUrls = function(dict){
  return Object.keys(dict).map(function(key){
      var item = dict[key];
      item.path = key;
      return item;
  }).sort(function(a, b){
      return a.vCount - b.vCount;
  });
}

var trck_urls = {
  '/home' : { 
      pageTitle: 't1',
      Visitors: ['oPc-Gr6SYxN1AMyw8Pst'],
      vCount: 1 },
  '/dash' : {
      pageTitle: 't2',
      Visitors: ['jepoSdBR9_ur3XSu8Psu', 'WIO4fEt1Ue8yHCly8Psv' ],
      vCount: 2 }
};

var sortedUrls = sortUrls(trck_urls);

In this case, Object.keys() gives you the list

['/home', '/dash']

and map lets you replace each of those keys with the corresponding data, thus coercing the original object to an array. Then the array can be sorted.

share|improve this answer
    
Hi Eric, I like a structure like this however I need to be able to get the vCount, Visitors and pageTitle by path. Thats why I chose to use the path as key. Or is there another way to get the values by path with this structure? – Tim K May 25 '14 at 20:44
    
I've updated my answer to show how you could store the data in an object, where the path is the key, and coerce that object to an array before sorting. – Eric May 27 '14 at 7:45
up vote 0 down vote

From the point of view of the sort function, what you are trying to sort is actually an empty array with a bunch of additional properties (/home, /dash). So if you want to sort them, you need to first create an array where the elements are the properties of your original array:

var array = [];
for (var key in nar) {
    array.push({key:key, value:nar[key]});
}
array.sort(function(a,b){
    return b.value.vCount - a.value.vCount;
}
share|improve this answer
    
Thanks Noziar. This works partially, unfortunately it breaks the Visitor array. – Tim K May 25 '14 at 20:46

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