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up vote 4 down vote favorite
1

I'm new in programming and I have an issue when doing the input validation. My program requires to input number from 1 to 10 or the letter y but it seems that I cannot do an error handler for this.

def checkingInput():
    while True:
        try:
            a = input()
            if 10 >= a >= 1 or a == 'y':
                return value
            else:
                print('Invalid input!')
        except NameError:
            print('Name error!Please try again!')
        except SyntaxError:
            print('Syntax Error!Please try again!')
share|improve this question
    
I presume you are using python 3 due to the print() but could you please confirm that? – jamylak May 10 '12 at 5:19
    
Yes i use python 3.1 – ScorpDt May 10 '12 at 5:25
2  
SyntaxError is not an exception that normally happens at runtime. – Ignacio Vazquez-Abrams May 10 '12 at 5:31
    
I think you want ValueError instead of SyntaxError. Also you can't compare ints with strings so you should change your line to if a == 'y' or 1 <= int(a) <= 10 – jamylak May 10 '12 at 5:32
1  
Thank you guys! – ScorpDt May 10 '12 at 5:55

1 Answer 1

up vote 4 down vote accepted

as jamylak suggested change the if condition to :

if a == 'y' or 1 <= int(a) <= 10:

program:

def checkingInput():
    while True:
        try:
            a = input('enter')
            if a == 'y' or 1 <= int(a) <= 10:
                return a
            else:
                print('Invalid input!')
        except ValueError:
            print('Value error! Please try again!')
share|improve this answer
    
doesn't work if a is 'y' since if statement checks conditions from left to right and won't be able to convert 'y' to int. Do this instead: if a == 'y' or 1 <= int(a) <= 10 – jamylak May 10 '12 at 5:37
    
@jamylak Thanks, I really didn't knew that If uses left to right checking. – Ashwini Chaudhary May 10 '12 at 5:47
    
+1 Also i can't tell if that is sarcasm or not... If it is I'm sorry but I just thought it was worth explaining for other people reading this. – jamylak May 10 '12 at 5:50
    
@jamylak no that isn't sarcasm, it was helpful. – Ashwini Chaudhary May 10 '12 at 6:00
    
Oh alright thanks then :D – jamylak May 10 '12 at 6:03

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