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up vote 1 down vote favorite

I get data from Json and there's a Json array. I want to convert that Json array into String array, so I can send it into another activity and show it in ListView.

Here's My java code

    if (jsonStr != null) {
        try {

            foodsFilter = new JSONArray(jsonStr);

            // looping through All Contacts
            for (int i = 0; i < foodsFilter.length(); i++) {

                JSONObject c = foodsFilter.getJSONObject(i);
                if(c.getString("category_name").equals("Food")) {
                String category_name = c.getString(TAG_CATEGORY_NAME);
                String filter_type = c.getString(TAG_FILTER_TYPE);
                //String item_list = c.getString(TAG_ITEM_LIST);
                JSONArray itemList = new JSONArray(c.getString("item_list"));
                String item_list = itemList.toString();

                // tmp hashmap for single contact
                HashMap<String, String> filter = new HashMap<String, String>();

                // adding each child node to HashMap key => value
                filter.put(TAG_CATEGORY_NAME, category_name);
                filter.put(TAG_FILTER_TYPE, filter_type);
                filter.put(TAG_ITEM_LIST, item_list);

                // adding contact to contact list
                foodsFilterList.add(filter);

                }
            }
        } catch (JSONException e) {
           e.printStackTrace();
        }
   }

I try that code to convert the JSONarray, but I realized that code is for convert the JSONArray into String.

Here's my JSON data

[{"category_name":"Food","filter_type":"Sort by","field_name":"","type":"VALUE","table_name":"","item_list":["Ascending","Descending"]}]

I want to convert the item_list Array into like this

item_list = {"Ascending", "Descending"}

So I can send it into another activity use Intent and show it in ListView

share|improve this question
    
Why not simply do this on the listview activity itself? Passing stuff using Intent is an expensive operation –  Leonardo Ferrari Jul 25 '14 at 3:32
    
Because I already have a listview on that activity. And I want to show that Data in another activity :D –  Matthew Jul 25 '14 at 3:40
    
@Matthew you can still parse the json in the listview activity itself. –  Raghunandan Jul 25 '14 at 3:48
    
@Raghunandan Do you mean, show the data on the same activity? –  Matthew Jul 25 '14 at 4:06
    
@Matthew you could show in the same activity or parse the data in Activity that has listview. passing through intent is expensive operation. If you can avoid it good –  Raghunandan Jul 25 '14 at 4:56

2 Answers 2

up vote 3 down vote accepted

What you have

String item_list = itemList.toString();

You need to parse items_list which is a JSONArray.

JSONArray itemList = new JSONArray(c.getString("item_list"));
// loop through the array itemList and get the items
for(int i=0;i<itemList.length();i++) 
{ 
String item = itemList.getString(i); // item at index i
}

Now you can add the strings to a list/array and then do what is required.

share|improve this answer
    
What If I have a dinamic data? Not just Ascend and Descend? –  Matthew Jul 25 '14 at 3:26
    
@Matthew you still be looping through the array from 0 to end of array and use the index to get the items required –  Raghunandan Jul 25 '14 at 3:27
    
there's an error on String item = itemsList.getString(i); // item at index i that the itemList variable cannot be resolved. –  Matthew Jul 25 '14 at 4:04
    
@Matthew where do you have that piece of code?. itemList is JSONArray itemList = new JSONArray(c.getString("item_list")); –  Raghunandan Jul 25 '14 at 4:55
1  
Thanks for your help. Its done. I really appreciate it –  Matthew Jul 25 '14 at 6:08
up vote 0 down vote

Please have a look on this tutorial.

http://www.androidhive.info/2012/01/android-json-parsing-tutorial/

Maybe this would help you. 

ArrayList<String> stringArray = new ArrayList<String>();
JSONArray jsonArray = new JSONArray();
for(int i = 0, count = jsonArray.length(); i< count; i++)
{
    try {
        JSONObject jsonObject = jsonArray.getJSONObject(i);
        stringArray.add(jsonObject.toString());
    }
    catch (JSONException e) {
        e.printStackTrace();
    }
}
share|improve this answer

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