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up vote 1 down vote favorite

I my php file, I need to make my own Json array.

        for($i=1;$i<$arraySize+1;$i++){
            $idJson[$i]=$i.":".$birdIDArray[$i-1];  
        }

        for($i=$arraySize+1 ;$i<$arraySize*2+1; $i++){
            $idJson[$i]=$i.":".$rankArray[$i-($arraySize+1)];
        }

When I use

print(json_encode($idJson));

the OUTPUT : ["0:3","1:15","2:3","3:14","4:1","5:2","6:2"]

But i need the output like this ["0":"3","1":"15","2":"3","3":"14","4":"1","5":2","6":"2"]

When I going to add " mark 

        for($i=1;$i<$arraySize+1;$i++){
            $idJson[$i]=$i.'"'.":".'"'.$birdIDArray[$i-1];  
        }

        for($i=$arraySize+1 ;$i<$arraySize*2+1; $i++){
            $idJson[$i]=$i.'"'.":".'"'.$rankArray[$i-($arraySize+1)];
        }

It prints like this ["0:3","1\":\"15","2\":\"3","3\":\"14","4\":\"1","5\":\"2","6\":\"2"]

How can I avoid from printing this \ sign?

share|improve this question
1  
why not simply json_encode($your_array);..? why do you want to create custom...? –  DemoUser Oct 7 '13 at 10:09
    
Why don't you just make a normal php array and use json_encode? –  Console Oct 7 '13 at 10:09
1  
["0":"3", ... is not a valid JSON array! –  deceze Oct 7 '13 at 10:13
    
I cannot simply encode my array to json because I need ID and Value pair to get data to my application with Json Object. –  Shashika Oct 7 '13 at 10:19

1 Answer 1

up vote 1 down vote accepted

I'm assuming you want a JSON object like this:

{"0":"3", ... }

The problem here is that Javascript/JSON distinguishes between key-value pairs, which are objects, and numerically indexed lists, which are arrays, while PHP uses arrays for both these things. With json_encode it depends on whether the PHP array is a continuously numerically indexed array, in which case you get a JSON array, or anything else, in which case you get a JSON object.

What you want is to force a JSON object even for a continuously numerically indexed array. The first question here would be: why?! But if you're really sure you want that (again, why?!), there's the JSON_FORCE_OBJECT flag in PHP 5.3+:

echo json_encode(array("3", "15", "3"), JSON_FORCE_OBJECT);
// {"0":"3","1":"15","2":"3"}

But I'll say again that that's pretty pointless. If you use a regular array like ["3","15","3"], the keys to those elements are already implicitly 0, 1 and 2. There's no need to enforce them as object keys.

share|improve this answer
    
JSONArray jarray=new JSONArray(result); for(int i=0;i<jarray.length();i++){ JSONObject json=jarray.getJSONObject(i); len=json.getString("0"); } previously I used json.getString(), but what can I use in here to get data from key0. –  Shashika Oct 7 '13 at 10:46
    
I have no idea what you're trying to tell me here. –  deceze Oct 7 '13 at 10:47
    
How can I get values in json array by calling the key(position of the array)? –  Shashika Oct 7 '13 at 10:50
    
In Android's Java? No idea. I can tell you that a JSON array ([3, 15, 3, ...]) seems to make the most sense for your data structure. How you work with that in Java I don't know. –  deceze Oct 7 '13 at 11:12
    
It's worked. It's easy to get values through indexes of JSON array. –  Shashika Oct 7 '13 at 17:04

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