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up vote 0 down vote favorite

I need convert arrays inside my parent array to objects to match my database model data.

I have array like this:

emails: Array[2] 
0: "[email protected]"
1: "[email protected]"
id: 1 
firstname: "Jane"
lastname: "Doe

What I want to achieve is to convert emails array to array of objects like this:

    emails: Array[2] 
    0: 
{
name: "[email protected]"
}
    1: 
{
name: "[email protected]"
}
    id: 1 
    firstname: "Jane"
    lastname: "Doe

I tried to use this code to convert array to object but for some reason it fails (no data are displayed -> variable rv is empty):

 var rv = {};
        for (var i = 0; i < dbInfo.emails.length; ++i)
            if (dbInfo.emails[i] !== undefined) rv[i] = dbInfo.emails[i];

Does someone knows why my code fails and does someone knows solution for this type of problem?

Thanks advance.

share|improve this question
    
stackoverflow.com/questions/2250953/… –  Vedant Terkar 19 hours ago
    
this code doesn't end up with rv being empty, unless dbInfo.emails is empty. I just tested it. –  forgivenson 19 hours ago
    
I can't even make sense of the way the OP has presented the desired input and output –  Alnitak 18 hours ago
    
Is the goal here to store the name and multiple email addresses for a user? If so, the data structure should be changed. The id, firstname and lastname properties are fine, but you should have an email property that is an array, containing the multiple email addresses. –  Jonathan M 18 hours ago

2 Answers 2

up vote 2 down vote accepted

This is a perfect use for the Array.prototype.map function:

dbInfo.emails = dbInfo.emails.map(function(e) {
    return { name: e };
});

i.e. just convert each individual element of the array (e) into an object { name: email }

share|improve this answer
    
Thank your for help. It's working perfectly. –  jureispro 18 hours ago
up vote 1 down vote

You are putting the emails into an object. Instead, you want to wrap each email in its own object, and put it back in the array.

for (var i = 0; i < dbInfo.emails.length; ++i) {
    if(dbInfo.emails[i] !== undefined) {
        dbInfo.emails[i] = { name: dbInfo.emails[i] };
    }
}
share|improve this answer

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