python convert string to integer with int(), syntax error, multiple statements found

Question

Im doing a very simple piece of code, and it keeps generating a Syntax error, multiple statements found while compiling a single statement. I cant see what is wrong with my code ! :( , please look at the link as my code typed here may be correct but I cannot see the difference between it and that in the IDLE linked.

I`m attempting to convert the string '10' to an integer so the if statement works.

here is the screen shot. http://www.screencast.com/t/0zItqcn5P6d

age = '10'
converted_age = int(age)
if converted_age == 10:
    print("whats the best way to speak to a monster?")
    print("from as far away as possible!")

Answer 1

age = '10'
converted_age = int(age)
if converted_age == 10:
                      ^ Colon needed here.
    print("whats the best way to speak to a monster?")
    print("from as far away as possible!")

Console session:

>>> age = '10'
converted_age = int(age)
if converted_age == 10:
    print("whats the best way to speak to a monster?")
    print("from as far away as possible!")
whats the best way to speak to a monster?
from as far away as possible!

In your screen shot you use ConvertedAge to store the variable but you compare with converted_age, and this gives an error as covnerted_age is not defined.

Answer 2

You are missing : after your if statement.

Well, I just executed

age = '10'
converted_age = int(age)
if converted_age == 10:
    print("whats the best way to speak to a monster?")
    print("from as far away as possible!")

with python2.7 and 3.0 and it seems ok to me. I can not reproduce it since you just said you have the same syntax above.

What is that orange line? Copy and paste exactly the same code above. Try it out.

Answer 3

You screen cast shows an error because converted_age is undefined.

you have convertedAge = int(age) and you are trying to compare undefined converted_age.