std::count, std::count_if
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Defined in header <algorithm>
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template< class InputIt, class T > typename iterator_traits<InputIt>::difference_type |
(1) | |
template< class InputIt, class UnaryPredicate > typename iterator_traits<InputIt>::difference_type |
(2) | |
Devuelve el número de elementos en el intervalo
[first, last)
satisfacer criterios específicos. La primera versión cuenta los elementos que son iguales a value
, la segunda versión cuenta con elementos para los cuales predicado p
vuelve true . Original:
Returns the number of elements in the range
[first, last)
satisfying specific criteria. The first version counts the elements that are equal to value
, the second version counts elements for which predicate p
returns true. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Contenido |
[editar] Parámetros
first, last | - | la gama de elementos a examinar
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
value | - | el valor a buscar
Original: the value to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
p | - | unary predicate which returns true para los elementos requeridos . Original: for the required elements The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. |
Type requirements | ||
-InputIt must meet the requirements of InputIterator .
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[editar] Valor de retorno
número de elementos que satisfacen la condición .
Original:
number of elements satisfying the condition.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Complejidad
exactamente
last
- first
comparaciones / aplicaciones del predicadoOriginal:
exactly
last
- first
comparisons / applications of the predicateThe text has been machine-translated via Google Translate.
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[editar] Posible implementación
First version |
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template<class InputIt, class T> typename iterator_traits<InputIt>::difference_type count(InputIt first, InputIt last, const T& value) { typename iterator_traits<InputIt>::difference_type ret = 0; for (; first != last; ++first) { if (*first == value) { ret++; } } return ret; } |
Second version |
template<class InputIt, class UnaryPredicate> typename iterator_traits<InputIt>::difference_type count_if(InputIt first, InputIt last, UnaryPredicate p) { typename iterator_traits<InputIt>::difference_type ret = 0; for (; first != last; ++first) { if (p(*first)) { ret++; } } return ret; } |
[editar] Ejemplo
El código siguiente
count
utiliza para determinar cómo muchos enteros en un std::vector de acuerdo con un valor objetivo .
Original:
The following code uses
count
to determine how many integers in a std::vector match a target value.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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#include <algorithm> #include <iostream> #include <vector> int main() { int data[] = { 1, 2, 3, 4, 4, 3, 7, 8, 9, 10 }; std::vector<int> v(data, data+10); int target1 = 3; int target2 = 5; int num_items1 = std::count(v.begin(), v.end(), target1); int num_items2 = std::count(v.begin(), v.end(), target2); std::cout << "number: " << target1 << " count: " << num_items1 << '\n'; std::cout << "number: " << target2 << " count: " << num_items2 << '\n'; }
Output:
number: 3 count: 2 number: 5 count: 0
En este ejemplo se utiliza un lambda expresión para contar elementos divisible por 3 .
Original:
This example uses a lambda expresión to count elements divisible by 3.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <algorithm> #include <iostream> #include <vector> int main() { int data[] = { 1, 2, 3, 4, 4, 3, 7, 8, 9, 10 }; std::vector<int> v(data, data+10); int num_items1 = std::count_if(v.begin(), v.end(), [](int i) {return i % 3 == 0;}); std::cout << "number divisible by three: " << num_items1 << '\n'; }
Output:
number divisible by three: 3