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I have a shell script and when invoking it ./test it asks for an input.I 've seen a quicker way just by writing at once ./test myInput ,how is that achievable?

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You can access the command line arguments in your shell script with the special variables $1, $2 until $9. $0 is the name of your script.

If you need access more than 9 command line arguments, you can use the shift command. Example: shift 2 renames $3 to $1, $4 to $2 etc.

Please remember to put the arguments inside doubles quotes (e.g. "$1"), otherwise you can get problems if they contain whitespaces.

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You can use "double-digit" parameters directly, just use braces: echo ${12} –  glenn jackman Dec 9 '13 at 18:19
    
Also, $# gives you the number of arguments. For example, with ./test.sh a b c, $# would evaluate to 3. –  DoxyLover Dec 9 '13 at 20:18

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