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I have an output for a command as below. 

Heading1
   I am one value.
   I am another value.
   I am third value. 
Heading2
   I am some value.
   I am someother value. 
   I am new value. 
Heading3

As we can see, there is a space in the beginning of the line if it is not a heading. I am trying to extract all the values under Heading1. I need the output as,

I am one value.
I am another value.
I am third value.

If I try the command,

grep mycommand | heading1

It gives me only the Heading1 line.

UPDATE:

I know, I have to extract the string from the starting of Heading1. But, I do not know the ending string (i.e, here I have mentioned as Heading2, but I won't be knowing it).

All I know is, I have to extract everything till the next heading which starts in a new line.

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3 Answers 3

up vote 1 down vote

Here is awk solution:

yourcommand | awk '/Heading1/ {for(n=0; n<3; n++) {getline; $1=$1; print}}'

Update

If between Heading1 and the end string only have lines start with space, you can do like this:

yourcommand | awk '/Heading1/ {flag=1;next} /^\w+/ {flag=0} {$1=$1} flag'
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up vote 1 down vote

Roughly how to do it:

$ sed -n -e '/Heading1/,/Heading2/ p' file.txt | grep "^ " | sed 's/^[ ]\+//g'
I am one value.
I am another value.
I am third value.

A bit more condensed version, makes use of pcregrep which allows for multiline matching:

$ pcregrep -M 'Heading1(\n|.)*Heading2' file.txt | grep "^[ ]\+"
   I am one value.
   I am another value.
   I am third value.

To get rid of the spaces at the begining using this method, you could make use of grep's PCRE facility:

$  pcregrep -M 'Heading1(\n|.)*Heading2' a.txt | grep -oP "^[ ]{3}\K.*"
I am one value.
I am another value.
I am third value.

Finally here's a sed and awk solution.

$ sed -n -e '/Heading1/,/Heading2/ p' file.txt | awk '/^ / {sub(/^[ ]+/, ""); print}'
I am one value.
I am another value.
I am third value.
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Thanks for the answer. What if I do not know the second string's name as Heading2? It can be anything and all I know is, a heading starts in that line.\ –  Ramesh Feb 8 '14 at 2:49
    
@Ramesh - do you know anything about it or not? –  slm♦ Feb 8 '14 at 2:58
    
No, I do not know anything about the second string. All I know is the first string. –  Ramesh Feb 8 '14 at 2:59
    
I will update my question with a proper example. –  Ramesh Feb 8 '14 at 2:59
up vote 1 down vote

This should work:

yourcommand | grep -A3 Heading1 | grep -v Heading1
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Explaining why that should work would be helpful... –  Potherca May 4 at 18:27

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