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#!/bin/bash

NEW_TEXT="if failed Send to Karn Kumarl"

OLD_FILE="$(awk '{print $1}' RMANJOBS | while read JB;do autorep -j $JB -q;done | egrep "^/|^insert_job|^description" | sed '0~3 a\\')"

NEW_FILE="MRMANJOBS"

AWK='''
    #.. Get new text from the shell variable.
    BEGIN { NewText = " " ENVIRON["TXT"] "\042"; }
    #.. If this line needs the fix, substitute the text.
    /^description:.* [Ii]f failed / { sub (/ [Ii]f failed .*$/, NewText); }
    #.. Print all lines, whether fixed or not.
    { print; }
    '''

TXT="${NEW_TEXT}" awk "${AWK}" "${OLD_FILE}" > "${NEW_FILE}"

Guys .. can anyone help me to sort the command output into a variable .. as its not taking for OLD_FILE.

share|improve this question
    
Does it work if you just get rid of the outer quotes? They aren't necessary and might be messing you up –  Eric Renouf Jul 27 at 18:22
    
@Eric - Even it doesn't work using without quotes like $().. While i am executing this script it simply display the command line output on the screen, while it should hold it and put it into NEW_FILE. –  karn Jul 27 at 18:43
    
Well, my standard next advice for this would be to put set -x at least before the line that's giving you trouble so you can see what it looks like when the variables are all expanded, perhaps you'll spot the issue that way. –  Eric Renouf Jul 27 at 18:51
    
I kept the set -x but it doesn't shows any issues though, Just prints the output of OLD_FILE on the screen. Only error i can see is "for reading (File name too long)" in the output. –  karn Jul 27 at 19:18
    
Can you show what is in OLD_FILE variable? (the output of awk '{print $1}' RMANJOBS | while read JB;do autorep -j $JB -q;done | egrep "^/|^insert_job|^description" | sed '0~3 a\\' command). Why you put empty lines after each 3rd? –  Costas Jul 27 at 19:30

1 Answer 1

up vote 0 down vote accepted 
#!/bin/bash

while read JB last
do
    autorep -j $JB -q
done < RMANJOBS |
sed -rn "/^\/|^insert_job|^description/{
    s/(description:.* [Ii]f failed )[^"]*/\1Send to Karn Kumarl/
    s/insert/update/
    p
    }" |
sed '0~3 G' > MRMANJOBS
share|improve this answer
    
@Costas- Can you explain Please –  karn Jul 27 at 22:23
    
This new script does not work .. it throws error for sed.. sed: -e expression #1, char 4: unknown command: `|' –  karn Jul 27 at 22:44
    
@karn Sorry I'd make / escaped. Test repaired. –  Costas Jul 28 at 7:52
    
@Costas 1- Though the solution working fine but here we forgot to "awk '{print $1}' RMANJOBS" Part to print the $1 as this has many feilds. 2- We need the last word to be closed with double quotes as below.<br/> description: "Unmount TCFTP filesystems on ABC - if failed Send to Karn Kumarl" <br/> 3- Can we replace the string altogether with sed in the below line which you suggested...<br/> sed -rn "/^\/|^insert_job|^description/ <br/> --> I need string "insert" to be replaced with "update" –  karn Jul 28 at 14:24
    
@karn 1/ You need not use awk due to read JB last which put in JB just 1st field. 2/ As I understand quotes there are in line already? 3/ I'm not sure to clear understand what you need. –  Costas Jul 28 at 14:31

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