What is the name of ** in python?

It's not an operator as such, so it doesn't really have a name, but it is defined as a "syntactic rule". So it should be called:

• "the keyword argument unpacking syntax"

If you have a list of arguments, *args, it's called "argument unpacking", in the same manner **kwargs is called "keyword argument unpacking".

If you use it on the left hand side of an =, as in a, *middle, end = my_tuple, you'd say "tuple unpacking".

In total, there are three types of (single parameter) arguments:

def f(x)  # x: positional argument
def f(x, y=0)  # y: keyword argument
def f(x, *xs, y=0)  # y: keyword-only argument

The *args argument is called the "variable positional parameter" and **kwargs is the "variable keyword parameter". Keyword-only arguments can't be given positionally, because a variable positional parameter will take all of the arguments you pass.

Most of this can be found in PEPs 0362 and 3102, as well as in the Control Flow section of the docs. It should be noted though that the function signature object PEP is only a draft, and the terminology might just be one person's idea. But they are good terms anyway. :)

So the * and ** arguments just unpack their respective data structures:

args = (1, 2, 3)  # usually a tuple, always an iterable*

f(*args) → f(1, 2, 3)

# and 

kwargs = {"a": 1, "b": 2, "c": 3}  # usually a dict, always a mapping*

f(**kwargs) -> f(1, 2, 3) # if ỳou have `def f(a=0, b=0, c=0)`

*: Iterables are objects that implement the __iter__() method and mappings are objects that implement __iter__() and __getitem__(). Any object that supports this protocol will be understood by the constructors tuple() and dict(), so they can be used for unpacking arguments.