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I have this PHP regex for remove utf8 special characters from strings:

[\x00-\x1F]|\xC2[\x80-\x9F]|\xE2[\x80-\x8F]{2}|\xE2\x80[\xA4-\xA8]|\xE2\x81[\x9F-\xAF]

I need to convert it to Javascript regex. I tryed this code:

str = str.replace(/[\x00-\x1F]|\xC2[\x80-\x9F]|\xE2[\x80-\x8F]{2}|\xE2\x80[\xA4-\xA8]|\xE2\x81[\x9F-\xAF]/g, '');

But it does nothing.

I need your help. Thank you.

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2 Answers 2

up vote 3 down vote

Simple mistake, big effect:

strTest = strTest.replace(/your regex here/g, "$1");
// ----------------------------------------^

without the "global" flag, the replace occurs for the first match only.

Side note: To remove any character that does not fulfill some kind of complex condition, like falling into a set of certain Unicode character ranges, you can use negative lookahead:

var regex = /(?![\x00-\x7F]|[\xC0-\xDF][\x80-\xBF]|[\xE0-\xEF][\x80-\xBF]{2}|[\xF0-\xF7][\x80-\xBF]{3})./g;
strTest = strTest.replace(regex, "")

where regex reads as

(?!      # negative look-ahead: a position *not followed by*:
  […]    #   any allowed character range from above
)        # end lookahead
.        # match this character (only if previous condition is met!)
share|improve this answer
up vote 0 down vote

Try this :

str = str.replace(/[\x00-\x1F]|\xC2[\x80-\x9F]|\xE2[\x80-\x8F]{2}|\xE2\x80[\xA4-\xA8]|\xE2\x81[\x9F-\xAF]/gi, '');
share|improve this answer
    
It do nothing.. – יוסי פיבקו Feb 21 at 19:46

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