Linux Shell Script Catching exit code after executing mysql script shell

I need to automate the mysql script execution in linux. If one sql script fails, it should not proceed further. It should come out of the script. I am using ${?} to test the exit status. But it's always returning the zero status though script has failed. I think it's returning zero because mysql command executed successfully even though script has failed with valid error. Please help me with the same. Also I want to know how to rollback if any script failed with valid error. Please check my code as below

#!/bin/bash
# Load the script and env configuration
. /home/base/scripts/conf/sql.conf
if ls ${HOME_PATH}/sql_actual/*.sql &> /dev/null; then
   for file in ${HOME_PATH}/sql_actual/*.sql
   do
       echo ${file}
       s=${file##*/}
       var_log=${s%.sql}
       echo ${var_log}
     mysql -u ${DB_USER} -p${DB_PASSWORD} -h ${DB_HOST} --default-character-set=utf8 ${DB_SCHEMA} < $file --silent --force -b 2>${HOME_PATH}/sql-logs/${var_log}.log
         if [ ${?} -ne 0 ]; then
        echo "${var_log}.sql SQL Script Failed to execute"
        exit ${?}
        else
        echo -e "${var_log}.sql" SQL Script executed successfully
        fi
done
else
    echo "files do not exist"
fi