Loop through array of strings in bash script?

That is possible, of course.

for databaseName in a b c d e f; do
  # do something
done 

See Bash Loops for, while and until for details.

In the same spirit as 4ndrew's answer:

listOfNames="RA
RB
R C
RD"

# To allow for other whitespace in the string:
# 1. add double quotes around the list variable, or
# 2. see the IFS note (under 'Side Notes')

for databaseName in "$listOfNames"   #  <-- Note: Added "" quotes.
do
  echo "$databaseName"  # (i.e. do action / processing of $databaseName here...)
done

# Outputs
# RA
# RB
# R C
# RD

B. No whitespace in the names:

listOfNames="RA
RB
R C
RD"

for databaseName in $listOfNames  # Note: No quotes
do
  echo "$databaseName"  # (i.e. do action / processing of $databaseName here...)
done

# Outputs
# RA
# RB
# R
# C
# RD

Notes

1. In the second example, using listOfNames="RA RB R C RD" has the same output.

Other ways to bring in data include:

• stdin (listed below),
• variables,
• an array (the accepted answer),
• a file...

Read from stdin

# line delimited (each databaseName is stored on a line)
while read databaseName
do
  echo "$databaseName"  # i.e. do action / processing of $databaseName here...
done # <<< or_another_input_method_here

Sides Notes

1. the bash IFS "field separater to line" [1] delimiter can be specified in the script to allow other whitespace (i.e. IFS='\n', or for MacOS IFS='\r')
2. I like the accepted answer also :) -- I've include these snippets as other helpful ways that also answer the question.
3. Including #!/bin/bash at the top of the script file indicates the execution environment.
4. It has taken me months to figure out how to code these simply :)

Other Sources (while read loop)

None of those answers include a counter...

#!/bin/bash
## declare an array variable
declare -a array=("one" "two" "three")

# get length of an array
arraylength=${#array[@]}

# use for loop to read all values and indexes
for (( i=1; i<${arraylength}+1; i++ ));
do
  echo $i " / " ${arraylength} " : " ${array[$i-1]}
done

Output:

1  /  3  :  one
2  /  3  :  two
3  /  3  :  three

You can use the syntax of ${arrayName[@]}

#!/bin/bash
# declare an array called array and define 3 vales
files=( "/etc/passwd" "/etc/group" "/etc/hosts" )
for i in "${files[@]}"
do
    echo $i
done

The declare array dont work for Korn shell. Use the below for example for korn shell:

promote_sla_chk_lst="cdi xlob"

set -A promote_arry $promote_sla_chk_lst 

for i in ${promote_arry[*]};
    do  
            echo $i
    done

Try this working and tested.

for k in ${array[@]}
do
   echo $k
done

# for accessing with echo command: echo ${array[0]}, ${array[1]}

If you are using Korn shell, there is "set -A databaseName ", else there is "declare -a databaseName"

To write a script working on all shells,

 set -A databaseName=("db1" "db2" ....) ||
        declare -a databaseName=("db1" "db2" ....)
# now loop 
for dbname in "${arr[@]}"
do
   echo "$dbname"  # or whatever

done

It should be work on all shells.

This is also easy to read:

FilePath=(
    "/tmp/path1/"    #FilePath[0]
    "/tmp/path2/"    #FilePath[1]
)

#Loop
for Path in "${FilePath[@]}"
do
    echo "$Path"
done

Possible first line of every bash script/session:

say() { for line in "${@}" ; do printf "%s\n" "${line}" ; done ; }

Use e.g.:

$ aa=( 7 -4 -e ) ; say "${aa[@]}"
7
-4
-e

May consider: echo interprets -e as option here