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I have a file (.htaccess) which contains below excerpt.

<Files wp-login.php>
order deny,allow
deny from all
allow from 45.152.35.2
</Files>

I need to replace 45.152.35.2 with my current IP. But 45.152.35.2 is not static. I need to find the IP expression at allow from line and replace it with my current IP.

I also need to get my current IP (75.152.35.4) from w command:

12:13:07 up 21 days,  3:01,  1 user,  load average: 0.18, 0.13, 0.12
USER     TTY      FROM              LOGIN@   IDLE   JCPU   PCPU WHAT
root     pts/0    75.152.35.4      14:29    0.00s  0.10s  0.00s w

How can I get current IP from w command and replace allow from line in .htaccess file?

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1 Answer 1

up vote 1 down vote

You can use this:

sed -i "s/allow from [0-9,\.]*/allow from $(w -h | awk '{print $3}' | head -1)/g" .htaccess

Explanation:

  • sed -i "s/.../$(...)/g .htaccess: replaces the allow from line with
  • w -h | awk '{print $3}' | head -1: the frist line of the output of w
share|improve this answer
    
I saw which is why I deleted my comment and instead upvoted :). You could also use sed -i -r "s/(allow from )[0-9\.]*/\1 $(w | awk '($NF=="w"){print $3}')/" .htaccess which has the added benefit of ensuring the right IP even if w returns multiple lines and multiple users. –  terdon♦ Sep 24 '14 at 22:09
    
@chaos works great but I want to change allow from line only for wp-login.php section. .htaccess file may contain many allow from lines. Your code replaces globally. How can it be done to change allow from line in wp-login.php section only? –  NecNecco Sep 24 '14 at 22:40

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