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Im currently trying to make a addition command in unix and have come up with the following code:
#! /bin/bash
#! Add - adds two given numbers together and displays the result
"$num1" = $1
"$num2" = $2
echo "Enter two numbers"
read num1 num2
sum=$(“$num1” + “$num2”)
echo "The sum is = $sum"
This however does not work.
((...)) is the way to do arithmetic, not single parens, and you don't need quotes there Try:
sum=$((num1+num2))
Ignoring the syntax errors in the script, it looks like the two numbers are given, i.e. they are present on the script's command line.
That means that the script could be reduced to
#!/bin/sh
printf 'The sum of %d and %d is %d\n' "$1" "$2" "$(( $1 + $2 ))"
This obviously does no verification of the passed arguments whatsoever. For example, it does not verify that there are exactly two arguments, and it also does not verify that they are decimal integers.
The script would be used as
$ ./script.sh -23 32
The sum of -23 and 32 is 9
num1=$1. No spaces, and the undecorated name on the left-hand side of the equal sign. Of course, those assignments are unnecessary, because you overwrite their values with the `read1 statement before you ever use them. – chepner Nov 25 '15 at 21:14