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up vote 1 down vote favorite

I am able to do this, 

array=(2 46 7 4 2 1 1 1 23 4 5)
store=(${array[*]:5:5})
echo ${store[@]}  # print 1 1 1 23 4 5

Now instead of extracting the 5 elements from position 5 from a user array, I need to extract command-line args from 5 and onward. I tried similar way but I am getting empty output

store=(${$[*]:5:5})  # <----------------- Something to be changed here?
echo ${store[@]}  # EMPTY OUTPUT

Any help, how to store n args from position mth onward in a array?

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1 Answer 1

up vote 4 down vote accepted

In bash (and also zsh and ksh93, the general form of parameter expansion or Substring Expansion is:

${parameter:offset:length}

If the length is omitted, you will get from offset to the end of parameter.

In your case:

array=(2 46 7 4 2 1 1 1 23 4 5)
store=( "${array[@]:5}" )
printf '%s\n' "${store[@]}"

will generate from 6th element to the last element.

With $@:

printf '%s\n' "${@:5}"

will generate from $5 to the end of positional arguments.

Also note that you need to quote the array variable to prevent split+glob operator on its elements.

With zsh, you can use another syntax:

print -rl -- $argv[5,-1]
share|improve this answer
    
Ok, I understand that, I am able to do it for user defined array, but my question is how do I extract from commandline args i.e $5 to end. –  mtk yesterday
    
@mtk: Just using it as-is. Added more details to the answer. –  cuonglm yesterday

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