How to Handle web based pop up in selenium webdriver using python

This example selects 'Ahmedabad'

from selenium import webdriver
driver = webdriver.Firefox()
driver.get("http://www.quikr.com")
driver.find_element_by_xpath("//*[@id='ctystlist']/div[1]/div[2]/ul[1]/li[1]/a")
driver.close()

Happy testing!

use below code to select chennai option,

FirefoxDriver driver = new FirefoxDriver();

    driver.get("http://www.quikr.com/");

    Wait<WebDriver> wait = new WebDriverWait(driver, 180);
    try {
        wait.until(new ExpectedCondition<WebElement>() {
            public WebElement apply(WebDriver driver) {
                // driver.switchTo().defaultContent();
                WebElement element = driver.findElement(By.xpath("//a[contains(text(),'Chennai')]"));
                if (element.isDisplayed()) {
                    return element;
                }
                return null;
            }
        });
    } catch (Exception e) {
        throw new RuntimeException("Exception while waiting for " + By.xpath("//a[contains(text(),'Chennai')]")
                + ". Exception:" + e + " on " + driver.getCurrentUrl());
    }


    driver.findElement(By.xpath("//a[contains(text(),'Chennai')]")).click();

    driver.close();