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I'm trying Pyramid by creating the new project. I choose PostgreSQL and sqlalchemy. For now I have a table "photo" created manually and a model for it:

class Photo(Base):
    """ The SQLAlchemy declarative model class for a Photo object. """
    __tablename__ = 'photo'

    id = Column(Integer, primary_key=True)
    name = Column(Text)
    filename = Column(Text)
    cat_id = Column(Integer)
    viewed = Column(Integer)
    created = Column(DateTime)

    def __init__(self, name):
        self.name = name

Then in a view I trying to filter some records:

walls = DBSession.query(Photo).filter(Photo.cat_id == 20).limit(10)

But this small bunch of code doesn't work, I had an error:

[sqlalchemy.engine.base.Engine][Dummy-2] {'param_1': 1, 'cat_id_1': 20}
*** sqlalchemy.exc.ProgrammingError: (ProgrammingError) relation "photo" does not exist
LINE 2: FROM photo 
             ^
 'SELECT photo.id AS photo_id, photo.name AS photo_name, photo.filename AS photo_filename, photo.cat_id AS photo_cat_id, photo.viewed AS photo_viewed, photo.created AS photo_created, photo.amazon_folder AS photo_amazon_folder \nFROM photo \nWHERE photo.cat_id = %(cat_id_1)s \n LIMIT %(param_1)s' {'param_1': 1, 'cat_id_1': 20}

DB connection url is correct:

sqlalchemy.url = postgres://me:pwd@localhost:5432/walls

Any suggestions?

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Are you SURE the SQL tables are created with the same names as you provided to SQLAlchemy? The table in PostgreSQL isn't actually called "photos" or "Photo"? (See answer on this question) –  Mark Hildreth May 12 '13 at 15:57

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