current community

your communities

more stack exchange communities

Stack Exchange Inbox Reputation and Badges
tour help
stack overflow careers
Sign up ×
Stack Overflow is a question and answer site for professional and enthusiast programmers. It's 100% free.
up vote 0 down vote favorite

I'm having problems with the method JSONObject sayJSONHello().

@Path("/hello")
public class SimplyHello {

    @GET
    @Produces(MediaType.APPLICATION_JSON)

     public JSONObject sayJSONHello() {      

        JSONArray numbers = new JSONArray();

        numbers.put(1);
        numbers.put(2);
        numbers.put(3);
        numbers.put(4);             

        JSONObject result = new JSONObject();

        try {
            result.put("numbers", numbers);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return result;
    }
}

In the client side, I want to get an int array, [1, 2, 3, 4], instead of the JSON

{"numbers":[1,2,3,4]}

How can I do that?

Client code:

System.out.println(service.path("rest").path("hello")
    .accept(MediaType.APPLICATION_JSON).get(String.class));

My method returns a JSONObject, but I want to extract the numbers from it, in order to perform calculations with these (e.g as an int[]).

I reveive function as a JSONObject.

 String y = service.path("rest").path("hello").accept(MediaType.APPLICATION_JSON).get(String.class);   
JSONObject jobj = new JSONObject(y);   
int [] id = new int[50];
 id = (int [] ) jobj.optJSONObject("numbers:");

And then i get error: Cannot cast from JSONObject to int[]

2 other way 

String y = service.path("rest").path("hello").accept(MediaType.APPLICATION_JSON).get(String.class);   
JSONArray obj = new JSONArray(y);  
int [] id = new int[50];      
 id = (int [] ) obj.optJSONArray(0);

And this time i get: Cannot cast from JSONArray to int[]...

It doesn't work anyway..

share|improve this question
2  
You can parse the json on the client side and get the number from the JSONArray right? How difficult would that be? –  R.J Nov 19 '13 at 10:23
1  
As @benzonico said, you can just access the JSON object's "numbers" element and gain access to the array –  nrathaus Nov 19 '13 at 10:23
    
Do you really think what you expect is different from what it is returning? If yes, then please type in the JSON object you are expecting :) –  dharam Nov 19 '13 at 18:27

2 Answers 2

up vote 4 down vote accepted

I've never used this, nor have I tested it, but looking at your code and the documentation for JSONObject and JSONArray, this is what I suggest.

// Receive JSON from server and parse it.
String jsonString = service.path("rest").path("hello")
    .accept(MediaType.APPLICATION_JSON).get(String.class);
JSONObject obj = new JSONObject(jsonString);

// Retrieve number array from JSON object.
JSONArray array = obj.optJSONArray("numbers");

// Deal with the case of a non-array value.
if (array == null) { /*...*/ }

// Create an int array to accomodate the numbers.
int[] numbers = new int[array.length()];

// Extract numbers from JSON array.
for (int i = 0; i < array.length(); ++i) {
    numbers[i] = array.optInt(i);
}

This should work for your case. On a more serious application, you may want to check if the values are indeed integers, as optInt returns 0 when the value does not exist, or isn't an integer.

Get the optional int value associated with an index. Zero is returned if there is no value for the index, or if the value is not a number and cannot be converted to a number.

share|improve this answer
    
Thanks for help! i missed in my code loop... –  volly Nov 20 '13 at 8:56
    
By the way, is any way to send numbers noit using numbers.put(1); .. ? e.g in loop ? will send 500 numbers.. –  volly Nov 20 '13 at 9:05
    
@volly Do not forget to accept an answer, if any solved your problem. There sure are a number of ways not to write every single number. E.g.: for (int i = 1; i <= 500; ++i) { numbers.put(i); } puts the numbers from 1 to 500, inclusive, in the array. If you already have the numbers in another array, the code to copy from the regular array to the JSON array is similar to this. E.g.: int[] myNumbers; /*...*/ for (int i = 0; i < myNumbers.length; ++i) { numbers.put(myNumbers[i]); } –  afsantos Nov 20 '13 at 9:58
up vote -1 down vote

Instead of -

result.put("numbers", numbers);

you can try (I haven't tested this though)

result.put(numbers);

Or iterate through the array "numbers" and put each one individually into the "result".

share|improve this answer
    
JSONObject likely has no method put(JSONArray). –  Danny Nov 19 '13 at 17:38
1  
Unless I am mistaken, there is no put method signature with only one parameter. It must have a key. –  Paul Richter Nov 19 '13 at 17:39

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.