Sed command usage without defining variables in shell script

Question

I have two variables

source_repo="fdl_ppe_01_04_repos_svc"
target_repo="fdl_ppe_01_10_repos_svc"

and I currently do a substitution within an XML file to replace all instances of $source_repo with $target_repo:

sed "s/$source_repo/$target_repo/g" $1 > $1_changed

How do I format the sed command so that it matches the pattern "fdl_ppe_01_XX_repos_svc" and replaces with $target_repo (XX can only be two digits)

...basically I don't want to have to define $source_repo in the script anymore

I'm struggling to understand sed syntax, so any help is appreciated!

Use source_repo="fdl_ppe_01_[0-9][0-9]_repos_svc", and always double quote your variable "$1". — cuonglm, Mar 9 at 9:03

GC 13 · Answer 1 · 2016-03-09 10:53:28Z

up vote 0 down vote

Used character matching in your sed command:

Character Class - [:digit:] = Numeric digits [0-9]

sed "s/fdl_ppe_01_[0-9][0-9]_repos_svc/$target_repo/g" $1 > $1_changed

$1_changed will give you desired output I believe.

answered Mar 9 at 10:53

GC 13

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