Simple Binary Adder

• Everything is in main. You need to make binary_add function, which only adds things. It may even return interesting things (aka condition flags).

• carry is not initialized.

• I don't see how do you use enum bool.

• I don't see why do you #include <conio.h>

• Be consistent with spaces. carry computation is very crowded. Make it

  (array[i] && dummy) || (dummy && carry) || (array[i] && carry)
  

Rather than converting to what is basically an integer array, which uses 16 bits per element, you'll find it much easier and more memory efficient to use a bitset<>, which stores 1 bit per element. With this you can cheat and convert the decimal addition to a bitset:

const size_t BIT_LENGTH = 9;

bitset<BIT_LENGTH> AddBinary(int numA, int numB)
{
    bitset<BIT_LENGTH> answer(numA + numB);
    return answer;
}

Or if you truly want bit manipulation something like this would work:

bitset<BIT_LENGTH> AddBinary(int numA, int numB)
{
    bitset<BIT_LENGTH> binaryA(numA);
    bitset<BIT_LENGTH> binaryB(numB);
    bitset<1> carry;
    for (int i = 0; i < BIT_LENGTH; i++)
    {
        bitset<2> temp(binaryA[i] + binaryB[i] + carry[0]);
        binaryA[i] = temp[0];
        carry[0] = temp[1];
    }
    return binaryA;
}

Now you can get the user to input integers and displaying the results is a simple matter of:

cout << AddBinary(numa,numb);