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up vote -3 down vote favorite

There are 4 shell scripts:

  1. Migrate a file from path-A to path-B (unix).
  2. This script triggers one powercenter work flow.
  3. This script triggers one IDQ job.
  4. This script deletes the file from path-B (refer point-1 script)

Now I need to create a shell script to call above mentioned scripts in sequence (Any script shall not start before previous is completed successfully).

I am absolutely new to unix.

share|improve this question
    
Can you please provide more details? As it stands, this a very generic question and is unlikely to give you helpful answers. Details like how the scripts are executed currently, whether they need to be called from a particular directory, etc would be helpful. – Munir Mar 8 at 16:48
1  
script1 && script2 && script3 && script4 – Jeff Schaller Mar 8 at 17:01
    
@munircontractor... Currently each script has to be triggered manually using bash.. Yes all scripts exist in a directory and called from same dir – Khushbu Chauhan Mar 8 at 17:32
up vote 1 down vote 
#! /bin/sh -
script1 &&
 script2 &&
 script3 &&
 script4

cmd1 && cmd2 runs cmd2 only if cmd1 succeeds. The exit status of a script is the exit status of the last run command.

Or:

#! /bin/sh -
set -e
script1
script2
script3
script4

set -e tells the shell to exit whenever a command fails (with the exit status of the failing command).

Or:

#! /bin/sh -
script1 || exit
script2 || exit
script3 || exit
script4

cmd1 || cmd2 runs cmd2 if cmd1 fails. exit exits the shell with the exit status of the last command (so here of the failing script). You can use exit 1 to force the exit status to be 1.

share|improve this answer
    
Thanks Stephane.. I shall try these.. Will keep you posted (tomorrow.. I am off work now) – Khushbu Chauhan Mar 8 at 17:34

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