Using Regex to grab multiple values from a string and drop them into an array?

Question

Trying to grab the two $ values and the X value from this string in Ruby/watir:

16.67%: $xxx.xx down, includes the Policy Fee, and x installments of $xxx.xx

So far I've got:

16.67%:\s+\$(\d+.\d{2})

which grabs the first xxx.xx fine, what do I need to add to it to grab the last two variables and load this all into an array?

F.J · Answer 1 · 2011-03-16 16:26:52Z

up vote 0 down vote accepted

You can use the following, but regex may be unnecessary if the surrounding text is always the same:

\$(\d+.\d{2}).*?(\d+) installments.*?\$(\d+.\d{2})

answered Mar 16 at 16:26

F.J
10.3k826

myarray = "16.67%: $xxx.xx down, includes the Policy Fee, and x installments of $xxx.xx".scan /\$\d+\.\d{2}/ – Dave McNulla Mar 16 at 19:35

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Mark O'Shea · Answer 2 · 2011-03-17 23:30:12Z

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/\$(\d+.\d{2}).+\$(\d+.\d{2})/ should do it. it wont matter what text is there, only that there are two "$" in the sentence.

answered Mar 17 at 23:30

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Chuck van der Linden · Answer 3 · 2011-03-16 17:54:26Z

up vote 0 down vote

Have you considered just splitting the string on the $ character?, then manipulating what you get with a regex or basic string commands?

answered Mar 16 at 17:54

Well I dont just need the two $ I need the number X before installments as well.. – SamuraiJack Mar 18 at 14:13

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sawa · Answer 4 · 2011-03-16 16:38:10Z

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You better use scan.

sub(/.*%/, '').scan(/\$?([\d\.]+)/)

answered Mar 16 at 16:25

sawa
6,2991618

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jreed121 · Answer 5 · 2011-03-16 16:22:07Z

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if you know that the text in between will always be the same you could just:

16.67%:\s+\$(\d+.\d{2}) down, includes the Policy Fee, and x installments of (\d+.\d{2})

answered Mar 16 at 16:22

only difference may be that the term Policy Fee may change.. thanks... – SamuraiJack Mar 16 at 16:40

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5 Answers