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up vote 1 down vote favorite

If I have an array of names like

names = ["Muneeb", "Roshan", "Umar", "Kamil", "Shamseer", "Ajay", "Jasar"]

and I want to filter this array in a way that select two elements from this array which has an index of 3 and 4. How to achieve this by AngularJS ng-repeat? Please advise.

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new_names = [names[3], names[4]] – xbonez Feb 25 '16 at 22:06
2  
Try ng-repeat="name in [names[3], names[4]]"? – Ananth Feb 25 '16 at 22:08
3  
Seems highly unlikely that you would only be using hard code index values. Please elaborate on full problem and show what you have attempted – charlietfl Feb 25 '16 at 22:10
up vote 0 down vote accepted

can use an ng-if on the index, something like

<div ng-repeat = "name in names track by $index">
  <div ng-if="$index === 3 || $index === 4">Whatever you want here</div>
</div>
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up vote 0 down vote

You can use ng-bind directive

Here is an example:

HTML

<main ng-app="myApp" ng-controller="MainController">

  <article ng-bind="arr[3]"></article>
  <article ng-bind="arr[4]"></article>

</main>

JS

angular.module('myApp', [])

  .controller('MainController', function($scope) {
    $scope.arr = ['one', 'two', 'three', 'four', 'five'];
  });
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