I have this code, in which I try to "glue" four bytes in order to construct an unsigned int. I shift left the bytes and "add" them using the OR operator.
unsigned long number1;
unsigned long number2;
unsigned long number3=0;
byte byte0 = 1;
byte byte1 = 40;
byte byte2 = 107;
byte byte3 = 238;
void setup(){
Serial.begin(9600);
}
void loop(){
number1 = byte1 <<8 | byte0 ; //(=10.241 O.K.)
//(should be 4.000.000.001, it produces 10.241)
number2 = byte3 <<24 | byte2 <<16 | byte1 <<8 | byte0;
//(should be 4.000.000.001, it produces 4.016.777.217)
number3 = number3 | byte3;
number3 = number3<<8;
number3 = number3 | byte2;
number3 = number3<<8;
number3 = number3 | byte1;
number3 = number3<<8;
number3 = number3 | byte0;
Serial.print("number1 = ");Serial.println(number1);
Serial.print("number2 = ");Serial.println(number2);
Serial.print("number3 = ");Serial.println(number3);
Serial.println(" ");
}
The problem is that the OR operator applies only to byte1 <<8 | byte0
and ignores the rest. That is number1 and number2 appear to have the same value (10241).
I also tried "adding" them up separately, as shown with number3, but it also produces a wrong result as well.
I tried the same code in python, and it works fine.
byte3, byte2, byte1, byte0 = 238, 107, 40, 1
print byte1 <<8 | byte0
print byte3 <<24 | byte2 <<16 | byte1 <<8 | byte0
number3 = 0;
number3 = number3 | byte3;
number3 = number3<<8;
number3 = number3 | byte2;
number3 = number3<<8;
number3 = number3 | byte1;
number3 = number3<<8;
number3 = number3 | byte0;
print number3
So, the question is:
Why both number2 and number3 produce a false result?