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up vote 6 down vote favorite
1

the eclipse tells that lang and i cant find a solution

Exception in thread "main" java.lang.NumberFormatException: For input string: "2463025552" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at Main.main(Main.java:31)

String s2[]=s.split("\\,");
Records rec=new Records();
rec.setName(s1[0]);
rec.setAddres(s2[0]);

phone  = Integer.parseInt( s2[1].trim() );
System.out.println(phone);

I read from file in this format name-adres,phone and ad in arraylist put for phone i have problem

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up vote 16 down vote

Integer.parseInt throws a NumberFormatException if the passed string is not a valid representation of an integer. here you are trying to pass 2463025552 which is out of integer range.

use long instead

long phone = Long.parseLong(s2[1].trim() )
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up vote 14 down vote

The real problem is that a phone number is not an integer. It is a String. You should not store it as a number, for reasons similar to the problem you are encountering now. The same applies for ZIP codes, sports team's jersey numbers, and a host of other "fake" numbers.

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+1 to Tom G, using Long or other numeric type can cause issues in future. – Alex Stybaev Dec 18 '12 at 14:38
1  
This is the correct response. What if the phone number is 000-0001. Do you really want to store it as 1? What would you show the user? – jsn Dec 18 '12 at 14:43
    
+1 tom, agreed ... way better to make it an string than long .. sad i dint get that tought while answering :P, – PermGenError Dec 18 '12 at 14:48
    
I tern the int varible to String ? – Βίκτορας ανδρεάδης Dec 18 '12 at 15:09
up vote 3 down vote

A Signed 32 Bit Integer can only read upto 2^31. You have to use a bigger datatype. long will get you up to 2^63.

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up vote 1 down vote

The basic thing is that, we don't need a phone number to be part of a arithmetic calculation like addition, subtraction etc. Hence we can take it as a String safely.

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up vote 0 down vote 
2463025552

is a out of range for int data type, try giving lesser number. Also check if it is in correct number format (like no spaces etc)

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It is a given phone number, we can't really change it so it fits into an int. – Paŭlo Ebermann Jul 5 '13 at 8:55
up vote 0 down vote

Change your data type to long or bigint. Your string is too long then int thats why it have exception..

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up vote 0 down vote

Integer.parseInt( s2[1].trim() ); here is your problem. So, change your parsing Integer to Long

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I change from Integer to long and works perfect.. A lot of thanks for help. – Βίκτορας ανδρεάδης Dec 19 '12 at 9:55

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