std::copy_backward
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Defined in header <algorithm>
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template< class BidirIt1, class BidirIt2 > BidirIt2 copy_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |
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Copia los elementos de la gama, que se define por
[first, last)
, a otro rango terminando en d_last
. Los elementos se copian en orden inverso (del último elemento se copia primero), pero su orden relativo se conserva .Original:
Copies the elements from the range, defined by
[first, last)
, to another range ending at d_last
. The elements are copied in reverse order (the last element is copied first), but their relative order is preserved.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Contenido |
[editar] Parámetros
first, last | - | la gama de los elementos para copiar
Original: the range of the elements to copy The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
d_last | - | final del rango de destino. Si está dentro de
d_last [first, last) , std::copy debe ser utilizado en lugar de std::copy_backward . Original: end of the destination range. If d_last is within [first, last) , std::copy must be used instead of std::copy_backward. The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Type requirements | ||
-BidirIt must meet the requirements of BidirectionalIterator .
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[editar] Valor de retorno
iterador hasta el último elemento copiado .
Original:
iterator to the last element copied.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Complejidad
Exactamente
last - first
tareas .Original:
Exactly
last - first
assignments.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Posible implementación
template< class BidirIt1, class BidirIt2 > BidirIt2 copy_backward(BidirIt1 first, BidirIt1 last, BidirIt2 d_last) { while (first != last) { *(--d_last) = *(--last); } return d_last; } |
[editar] Ejemplo
#include <algorithm> #include <iostream> int main() { std::vector<int> from_vector; for (int i = 0; i < 10; i++) { from_vector.push_back(i); } std::vector<int> to_vector(15); std::copy_backward(from_vector.begin(), from_vector.end(), to_vector.end()); std::cout << "to_vector contains: "; for (unsigned int i = 0; i < to_vector.size(); i++) { std::cout << to_vector[i] << " "; } }
Output:
to_vector contains: 0 0 0 0 0 0 1 2 3 4 5 6 7 8 9
[editar] Ver también
(C++11) |
Copia un intervalo de elementos a una nueva ubicación Original: copies a range of elements to a new location The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (función de plantilla) |