I have a problem with this piece of code because it does't work but it seems to be semantically correct. It arrive up to "die("Errore nella query: $query.");" but I can't understand why. Help me please:
<?php
// Connessione al DB Server
$conn = mysqli_connect("localhost","root","","mydb");
// Controllo
if (!$conn){
echo "connessione database fallita";
exit();
}
$nome = $_POST["nm"];
$cognome = $_POST["cgn"];
$email = $_POST["ml"];
$username = $_POST["nkn"];
$password = md5($_POST["psw1"]);
$nome = mysqli_real_escape_string($conn,trim($nome));
$cognome = mysqli_real_escape_string($conn,trim($cognome));
$email = mysqli_real_escape_string($conn,trim($email));
$username = mysqli_real_escape_string($conn,trim($username));
$password = mysqli_real_escape_string($conn,trim($password));
$query = "SELECT username FROM utenti WHERE username = '".$username."'";
$risultato = mysqli_query($conn,$query);
if (!$result) {
die("Errore nella query: $query.");
}
$riga = mysqli_fetch_array($risultato,MYSQLI_NUM);
$n = mysqli_affected_rows($conn);
if($n >= 1){
echo "Username non disponibile";
}else{
$inserisci = "INSERT INTO utenti (nome,cognome,email,username,password) VALUES ('$nome','$cognome','$email','$username','$password')";
mysqli_query($conn,$inserisci);
?>
<p>Utente: <?php echo $username ?> registrato con successo.</p>
<?php
}
mysqli_close($conn);
?>
