Change exit code from 0 to 1 in bash script

Question

I have a script that rsyncs and ends like this

rsync -azvh /dir -e ssh [email protected]:/
RESULT="$?"

# check result of rsync db's
if [ "$RESULT" != "0" ]; then
    echo -e "rsync exit Code:" $RESULT "\nFAILED to rsync backups"
else
    echo "SUCCESSFULL rsync of backups"
fi

I have just been asked to wrap it in an API but the API states that 0=fail and 1=success. How can I change the exit code to reflect this? Do I need to assign it a variable?

Answer 1

exit 1 will exit with an error code of 1 and exit 0 will exit with an error code of 0.

For instance:

rsync -azvh /dir -e ssh [email protected]:/
RESULT="$?"

# check result of rsync db's
if [ "$RESULT" != "0" ]; then
    echo -e "rsync exit Code:" $RESULT "\nFAILED to rsync backups"
    exit 0
else
    echo "SUCCESSFULL rsync of backups"
    exit 1
fi

Answer 2

Revised answer, report false (exit 1 would work too), and true as needed as per non-standard API:

rsync -azvh /dir -e ssh [email protected]:/
RESULT="$?"
# check result of rsync db's
if [ "$RESULT" = "0" ]; then
    echo "SUCCESSFULL rsync of backups"
    false
else
    echo -e "rsync exit Code:" $RESULT "\nFAILED to rsync backups"
    true
fi

Answer 3

super easy via bash:

test $((`echo "${PIPESTATUS[@]}" | tr ' ' '+'`)) -eq 0
echo $?