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up vote 6 down vote favorite

I have an array:

var a = [2,3,4,5,5,4]

I want to get unique array out of given array like

b = [2,3,4,5]

I have tried 

a.filter(function(d){return b.indexOf(d)>-1})

and I don't want to use for loop.

share|improve this question
    
stackoverflow.com/questions/9229645/… – Sharath Bangera 9 hours ago
    
Here are multiple examples - jstips.co/en/deduplicate-an-array with newer ES syntax, and future implementations (using Array Sets) – ioneyed 9 hours ago
    
use lodash library ( lodash.com/docs/#uniq) – Pratap 9 hours ago
up vote 6 down vote accepted

you can simply do it in java script , with the help of filter second parameter which is for indexing like this

var a = [2,3,4,5,5,4]
a.filter(function(d,i){return a.indexOf(d)==i})
share|improve this answer
    
I will be happy if u explain this "function(d,i){return a.indexOf(d)==i}" – Mohammad Sadiqur Rahman 9 hours ago
1  
i in parameter is for indexing , means when you check for second last 5 , index would be 4 but indexOf would be 3 so they dont match hence it wiill filter out – Ashu 8 hours ago
    
Thanks.You have given a simple,tricky and great answer to this problem – Mohammad Sadiqur Rahman 8 hours ago
up vote 1 down vote

This is not an Angular related problem. It can be resolved in a couple of ways depending which libraries you are using.

If you are using jquery:

var uniqeElements = $.unique([2,3,4,5,5,4]);

The output would be:

[2,3,4,5]

If you are using underscore:

var uniqeElements = _.uniq([2,3,4,5,5,4]);

Same output.

And pure JS code:

var unique = [2,3,4,5,5,4].filter(function(elem, index, self) {
    return index == self.indexOf(elem);
})
share|improve this answer
up vote 0 down vote 
var b = a.filter( function( item, index, inputArray ) {
       return inputArray.indexOf(item) == index;
});
share|improve this answer
1  
Please add some explanation to your code – Yury Fedorov 6 hours ago

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