I am trying to create a piece of code that takes an input from the user and searches for that input in his gmail account and then checks all the boxes from the sender which is the same as the input. Here is my code:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from bs4 import BeautifulSoup
from selenium.webdriver import Remote
from selenium.webdriver.support.ui import WebDriverWait
import urllib
driver = webdriver.Chrome('D:/chromedriver_win32/chromedriver.exe')
driver.get("http://www.gmail.com")
elem = driver.find_element_by_id('Email')
elem.send_keys("****************")
elem2 = driver.find_element_by_id('next')
elem2.send_keys(Keys.ENTER)
driver.maximize_window()
driver.implicitly_wait(20)
elem3 = driver.find_element_by_name('Passwd')
elem3.send_keys("*************")
driver.find_element_by_id('signIn').send_keys(Keys.ENTER)
driver.implicitly_wait(20)
inp = 'randominput'
driver.find_element_by_name('q').send_keys(inp)
driver.find_element_by_css_selector('button.gbqfb').send_keys(Keys.ENTER)
x = driver.current_url
for i in driver.find_elements_by_css_selector('.zA.zE'):
print(i.find_element_by_class_name('zF').get_attribute('name'))
if(i.find_element_by_class_name('zF').get_attribute('name') == inp):
i.find_element_by_css_selector('.oZ-jc.T-Jo.J-J5-Ji').click()
This main problem is that although the webdriver shows the new page where it has searched for the query but when the code interacts with the page it interacts with the previous one.
I have tried putting implicit wait. And when I check for the current url it shows the new url.