Top new questions this week:
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I found at Twitter that is possible to search for arXiv articles with Mathematica, e.g. the following code:
arXiv = ServiceConnect["ArXiv"];
articles = arXiv["Search", {"Query" -> "Mathematica"}];
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I was told that I could obtain an analytic solution to a particle falling under the influence of Newtonian gravity by using DSolveValue.
What I am given
$G = M = m = 1$
$M$ is a point mass at $z=0$
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Bug introduced in 10.0 and persisting through 11.0 (reported as CASE:3790525)
Here's a simple series:
Sum[t^k DiscreteDelta[k]/k!,{k,0,Infinity}]
Mathematica says that it doesn't converge. But ...
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I have two lists liste = {x, -y, y, -z} and listv = {1, -2, 3, -4}, which represent the inequities obtained evaluating liste - listv <= 0. How do I reassemble or join those two separate lists into ...
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Someone recently posted a request on LinkedIn for an algorithm to find the largest palindrome from a given string.
I came up with this, which I believe does the trick, but I am wondering if there ...
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Here is the example, copied from here
square = Function[x, x^2];
square1 = #^2 &;
the timing and unpacking status shows
data = RandomReal[{0, 10}, {10000}];
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I have some points from a triangle,but there are some unexpected point still.How to remove those singular point and find the most probable triangle?
SeedRandom[8]
triPoint =
RandomPoint[
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Greatest hits from previous weeks:
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I'm building a package to help me write packages and their documentation. In this post I explained how to make a package and its documentation. In the answer I provided I describe how to build a very ...
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I need to play with a lot of powers such as 10^-3. 1E-3 does not work for it. Is there any short form for it?
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Can you answer these?
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I'm reading a book that has the following theorem:
I am trying to make Mathematica perform these calculations for me. Is it possible to do it without having to declare the matrices? For ...
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I stumbled over the following weird behavior when comparing floating-point numbers close to 1.0:
qq = 1.0 + 60.0 $MachineEpsilon;
and then
qq > 1.0
yields False. However,
qq - 1
yields
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When I execute the following code
y = Ceiling[π, 0.001]
3.142
For[i = 0, i <= 10, i = i + 0.001,
If[Floor[i/y] == 1,
Print[i];
Print[i - 0.001, " ", Floor[(i - 0.001)/y]];
...
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