PHP Parse error: syntax error, unexpected '!'

Question

HI I'm trying to figure out how a piece o sample code works but when I try and run it I get the above error. Kindly find line below

       if(!$_POST['user']    !$_POST['pass']){      //Affected Line 
         die('You did\'t fill in a required field.');   

   }

Thanks

!$_POST['user'] !$_POST['pass'] And what kind of fancy condition should that be? — Rizier123
– Rizier123, Commented Mar 31, 2015 at 18:12

kainaw · Accepted Answer · 2015-03-31 18:12:20Z

2

You need a logical operator. I assume you want "or"

if(!$_POST['user'] || !$_POST['pass'])

I would personally check to see if they are empty:

if(empty($_POST['user']) || empty($_POST['pass']))

answered Mar 31, 2015 at 18:12

kainaw

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1 Comment

Thanks it worked almost wanted to ask why then after having a look it makes sense. Thanks again