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up vote 9 down vote favorite
4

Let say I have an array object

[{
    name: 'a',
    number: 1
},
{
    name: 'b',
    number: 2
},
{
    name: 'c',
    number: 3
}]

And I just want to get the name:'b' which is array[1] values. How to pass it to the filter?

<li ng-repeat="foo in foos | filter:what_to_do_here="b"><li>
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2 Answers 2

up vote 20 down vote accepted 
<li ng-repeat="foo in foos | filter:{name:'b'}">{{foo.name}}</li>
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1  
suppose there's another object in the list {name:'abc',number:100}, then this filter will also select this object because it contains b in name attributes. is there anyway to alter the comparison behavior from 'contains' to exact match? – Bilal Mirza Sep 12 '13 at 11:04
1  
See if this helps: stackoverflow.com/a/18243147/1095616 – Stewie Sep 12 '13 at 15:58
    
Thanks @Stewie, I've just resolved it in same way. – Bilal Mirza Sep 13 '13 at 6:12
    
Is there anyway to apply a not filter to this? For example, all objects whose name is not 'b'? – Conqueror Nov 7 '13 at 22:19
    
Yes, prepend the search string with !: <li ng-repeat="foo in foos | filter:{name:'!b'}">{{foo.name}}</li>. Btw, this filters out those items which contain letter "b". For the exact match filtering see the comment link above. – Stewie Nov 8 '13 at 10:07
up vote 1 down vote 
<li ng-repeat="foo in foos | filter:'b'">{{foo.name}}</li>

might work as well

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Sure, but vzhen wants to filter by name explicitly. – Stewie Apr 2 '13 at 12:29

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