Codeigniter : Parse error: syntax error, unexpected end of file on my View [duplicate]

Add spaces in between <?php and }

so that you code will be :

<select name="kode_jenis_obat" class="form-control" action="<?php echo form_dropdown('kode_jenis_obat',$hasil->kode_jenis_obat);?>">
    <option>Pilih Jenis Obat</option>
    <!-----Displaying fetched cities in options using foreach loop ---->
    <?php foreach ($kode_jenis_obat as $isi)
    {
          if($isi->kode_jenis_obat == $isi->kode_jenis_obat)
          { ?>
             <option value="<?php echo $isi->kode_jenis_obat; ?>"><?php echo $isi->nama_jenisobat?></option>
      <?php } else {?>
             <option value="<?php echo $isi->kode_jenis_obat; ?>"><?php echo $isi->nama_jenisobat?></option>
      <?php } } ?>
</select>

Just replace your code by this:

also dynamic array you have

and don't put action attribute in select

  <div class="form-group">
         <label for="exampleInputJenis">Jenis Obat</label>
         <div class="input-group">
            <span class="input-group-addon"><i class="fa fa-list"></i></span>
           <select name="kode_jenis_obat" class="form-control" >
            <option>Pilih Jenis Obat</option>

                <?php 
                $kode_jenis_obat = array('kode_jenis_obat','kode_jenis_obat');
                foreach ($kode_jenis_obat as $isi)
                {
                  if($isi[0] == $isi[0])
                  {?>
                  <option value="<?php echo $isi['0']; ?>"> <?php echo $isi['1']?> </option>
                  <?php }
                  else 
                  {?>
                  <option value="<?php echo $isi['0']; ?>"> <?php echo $isi['1'];?> </option>
                  <?php }
                }
                  ?>
              </select>

          </div>
        </div>