Unix shell scripting select and case statement

Question

1) i want to write unix script which is like this

echo "Do u want to check application logs ???"
select opt in Yes No
    do
    case $opt in
    "Yes")
         commmands
     ;;
    "No")
    break
        ;;
    esac
    done

echo "Do u want to check non-application logs ???"
select opt in Yes No
    do
    case $opt in
    "Yes")
         commmands
     ;;
    "No")
    break
        ;;
    esac
    done

here after executing the first part its exiting and its asking the same thing again and again its not going to the other part i.e non-application logs

2)is this possible to use the two select and two case statements in the unix shell scripting if it is do please let me knoe the syntax.

Answer 1

From the bash help on select:

select: select NAME [in WORDS ... ;] do COMMANDS; done
...
COMMANDS are executed after each selection until a break command is executed

The break command you do have in there is breaking the case, not the select. You need to put a break outside the case block.

For example:

echo "Do u want to check application logs ???"
select opt in Yes No
do
    case $opt in
    "Yes")
        commmands
        ;;
    esac
    break
done

Also, since this case only has a single action, you might as well use an if, but I'll leave that to you.