Populate PHP Array from While Loop

This will do the trick:

$rows = array();
$result = mysql_query("SELECT * FROM `Departments`");
while($row = mysql_fetch_assoc($result))
{
  $rows[] = $row;
}

This has been one of the fastest ways for me to create (multi-dimensional) arrays. I'm not sure if you want all of your results smooshed into one array or not.

// Read records
$query = "SELECT * FROM `Departments`"; 
$query = mysql_query($query);

// Put them in array
for($i = 0; $array[$i] = mysql_fetch_assoc($query); $i++) ;

// Delete last empty one
array_pop($array);

You can use print_r($array) to see the results.

my fav is the following;

$result=odbc_exec($conn,$sql);
if ($result) {
    while($found_results[] = odbc_fetch_array($result)) { } 
    array_pop($found_results); //pop off the empty line from while loading
}

you dont need to pop the last line, but it does leave a blank if you omit it. works the same for mysql obviously.

If you have multiple columns in your Departments table and you want to save in different array.

$result = mysql_query("SELECT * FROM `Departments`");
$dept_id = array();
$dept_name=array();
while($row = mysql_fetch_assoc($result))
{
//fetches and store all results in id column on your departments table
$dept_id= $row['id'];
//fetches and store all results in name column on your departments table    
$dept_name=$row['name'];
}