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up vote 16 down vote favorite
9

I'm very new to java play framework. I've set up all the normal routes like /something/:somthingValue and all the others. Now I want to create route the accepts query parameters like

/something?x=10&y=20&z=30

Here I want to get all the params after "?" as key==>value pair.

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up vote 26 down vote accepted

You can wire in your query parameters into the routes file:

http://www.playframework.com/documentation/2.0.4/JavaRouting in section "Parameters with default values"

Or you can ask for them in your Action:

public class Application extends Controller {

    public static Result index() {
        final Set<Map.Entry<String,String[]>> entries = request().queryString().entrySet();
        for (Map.Entry<String,String[]> entry : entries) {
            final String key = entry.getKey();
            final String value = Arrays.toString(entry.getValue());
            Logger.debug(key + " " + value);
        }
        Logger.debug(request().getQueryString("a"));
        Logger.debug(request().getQueryString("b"));
        Logger.debug(request().getQueryString("c"));
        return ok(index.render("Your new application is ready."));
    }
}

For example the http://localhost:9000/?a=1&b=2&c=3&c=4 prints on the console:

[debug] application - a [1]
[debug] application - b [2]
[debug] application - c [3, 4]
[debug] application - 1
[debug] application - 2
[debug] application - 3

Note that c is two times in the url.

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I'm not able to see getQueryString() method of request(). is it because I'm using play 2.0 and you're using 2.0.4 ? – Sadik Apr 9 '13 at 18:22
    
You are right, playframework.com/documentation/api/2.0/java/play/mvc/… does not contain getQueryString() but request().queryString() can give you all you need. – Schleichardt Apr 9 '13 at 18:27
    
Thanks a lot man. can you suggest me some good tutorials on it? Except it's documentation. – Sadik Apr 9 '13 at 18:53
2  
Great, then please mark my answer accepted. A list of Play tutorials can be found on groups.google.com/forum/?fromgroups=#!topic/play-framework/… – Schleichardt Apr 9 '13 at 19:05
    
One more issue, as play 2.0 has not getQueryString() method and Arrays.toString(entry.getValue()) returns value with [] what if I don't want those [] ? I just want value as we're getting with getQueryString() method. Do I've to switch to latest version of Play ? – Sadik Apr 10 '13 at 7:16
up vote 6 down vote

You can get all query string parameters as a Map:

Controller.request().queryString()

This method return a Map<String, String[]> object.

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up vote 3 down vote

In Play 2.5.x, it is made directly in conf/routes, where one can put default values:

# Pagination links, like /clients?page=3
GET   /clients              controllers.Clients.list(page: Int ?= 1)

In your case (when using strings)

GET   /something            controllers.Somethings.show(x ?= "0", y ?= "0", z ?= "0")

When using strong typing:

GET   /something            controllers.Somethings.show(x: Int ?= 0, y: Int ?= 0, z: Int ?= 0)

See: https://www.playframework.com/documentation/2.5.x/JavaRouting#Parameters-with-default-values for a longer explanation.

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up vote 0 down vote

In Java/Play 1.x you get them with:

    Request request = Request.current();
    String arg1 = request.params.get("arg1");

    if (arg1 != null) {
        System.out.println("-----> arg1: " + arg1);
    }
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