std::atanh
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Defined in header <cmath>
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float atanh( float arg ); |
(desde C++11) | |
double atanh( double arg ); |
(desde C++11) | |
long double atanh( long double arg ); |
(desde C++11) | |
double atanh( Integral arg ); |
(desde C++11) | |
Calcula la tangente hiperbólica del arco
arg
Original:
Computes hyperbolic arc tangent of
arg
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You can help to correct and verify the translation. Click here for instructions.
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Contenido |
[editar] Parámetros
arg | - | flotando valor en puntos
Original: floating point value The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[editar] Valor de retorno
tangente hiperbólica inversa de
arg
Original:
inverse hyperbolic tangent of
arg
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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[editar] Ver también
(C++11) |
arco seno hiperbólico Original: hyperbolic arc sine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (función) |
(C++11) |
hiperbólico arco coseno Original: hyperbolic arc cosine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (función) |
tangente hiperbólica Original: hyperbolic tangent The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (función) | |
(C++11) |
calcula arcotangente hiperbólica de un número complejo Original: computes hyperbolic arc tangent of a complex number The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (función de plantilla) |
[editar] Enlaces externos
Weisstein, Eric W. "Inverse Hyperbolic Tangent." De MathWorld - Un recurso del Web Wolfram .
Original:
Weisstein, Eric W. "Inverse Hyperbolic Tangent." From MathWorld--A Wolfram Web Resource.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
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